How many moles of oxygen atom is there in 18.02 grams of Barium Phosphate.

To find the number of moles of oxygen atoms in 18.02 grams of barium phosphate, Ba2(PO4)2, we need to determine the molar mass of barium phosphate and the number of oxygen atoms in one mole of the compound.

The molar mass of barium phosphate is:

2 x 137.327 g/mol (barium) + 2 x 231.964 g/mol (phosphorus) + 8 x 15.999 g/mol (oxygen) = 511.20 g/mol

There are 8 oxygen atoms in one mole of barium phosphate because the compound has two phosphate groups, each of which contains four oxygen atoms.

So, the number of moles of oxygen atoms in 18.02 grams of barium phosphate is:

18.02 g / 511.20 g/mol = 0.035 moles

Therefore, there are 0.035 moles of oxygen atoms in 18.02 grams of barium phosphate.