How do you balance the following reaction: Cl2(g)+NaOH(aq)→NaCl(aq)+NaClO3(aq)+H2O(l)

To balance this chemical equation, you need to make sure that there is the same number of each type of atom on both sides of the arrow.

Here is the balanced equation:

2 Cl2(g) + 2 NaOH(aq) → 2 NaCl(aq) + NaClO3(aq) + H2O(l)

I'll go through the steps to balance the equation:

Start by counting the number of atoms of each element on each side of the arrow. You'll see that there are two chlorine atoms on the left side of the arrow, but only one on the right side. To balance the number of chlorine atoms, add a coefficient of 2 in front of NaClO3(aq). This gives us:

Cl2(g) + NaOH(aq) → NaCl(aq) + 2 NaClO3(aq) + H2O(l)

Now count the number of sodium atoms on each side of the arrow. You'll see that there is one sodium atom on the left side and two on the right side. To balance the number of sodium atoms, add a coefficient of 2 in front of NaOH(aq). This gives us:

Cl2(g) + 2 NaOH(aq) → 2 NaCl(aq) + 2 NaClO3(aq) + H2O(l)

Finally, count the number of oxygen atoms on each side of the arrow. You'll see that there are two oxygen atoms on the left side and four on the right side. To balance the number of oxygen atoms, add a coefficient of 2 in front of H2O(l). This gives us the balanced equation:

2 Cl2(g) + 2 NaOH(aq) → 2 NaCl(aq) + 2 NaClO3(aq) + 2 H2O(l)