The sum of three consecutive multiples of 8 is 888. Find the multiples.

The sum of three consecutive multiples of 8 is 888. Find the multiples.

This question is from Class 8 Maths NCERT Chapter 2 Linear Equations in One Variable Exercise 2.2 Question 7.

Solution: 

To solve this question, we need to form a linear equation. 

Let the first multiple of 8 be x.  

Then second consecutive multiple of 8 will be x + 8, 

Third consecutive multiple of 8 will be x + 8 + 8 = x + 16.

 As it's given in the question, 

The Sum of three consecutive multiples of 8 is 888. 

 ⇒ x + x + 8 + x + 16 = 888 

 ⇒ 3x + 24 = 888 

 ⇒ 3x = 888 - 24 

 ⇒ 3x = 864 

 ⇒ x = 864/3 

 ⇒ x = 288 

 Therefore, x + 8 = 296, x + 16 = 304. 

 Thus, the multiples of 8 are 288, 296, and 304.

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